how to do (4-4x+X^2)/2-X y=lim x->1 thank you!

4 - 4x - x^2 = (2 - x)^2; cancel with the (2 - x) from the denominator and get limit x ->1 of (2 - x) which is 1.

thank Lilian! I just plug 1 into all the X and get the answer of 1 too. Do you think it is correct if i do the same thing on other similar questions like that?

Well, the method can be applied but you have to be careful as some problems may require a bit of attention for the denominator. At first glance you may want to say that the limit is not defined when x = 2. But after you cancel the denominator, the situation change. So, use the same method but not with the same results.

..I wanted to say that you cannot expect the same results.

so that best way to solve this kind of question is to cancel out the terms first?

only if you can. There are situations and situations. You were lucky this time :)

what happened if the lim X->1+ then?

so i need to plug 1.1 into the X after cancel out all the terms?

Yes. Reduce at much as you can and than work out.

you are so helpful Lilian, I have been seeking for help for a whole day, finally found someone can help me out with it. thank you!

if i put limit X->1+ for this question, will the answer going to be 1 or infinitive?

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